Haskell: Take a list and print their position

For example, if a list has employees like ["Hari Krishna", "PTR", "Nayan", "Sudhir"], then output should be like [(1, "Hari Krishna"), (2, "PTR"), (3, "Nayan"), (4, "Sudhir")].

ListUtil.hs

getNumbers :: Int -> Int -> [Int]
getNumbers x y
    | (x == y) = []
    | (x > y) = getNumbers' x y (-1)
    | otherwise = getNumbers' x y 1

getNumbers' :: Int -> Int -> Int -> [Int]
getNumbers' x y increment
    | (x == y) = [y]
    | otherwise = x : (getNumbers' (x+increment) y increment)

getIndexes :: [a] -> [(Int, a)]
getIndexes [] = []
getIndexes xs = getIndexes' xs (getNumbers 1 (length xs))

getIndexes' :: [a] -> [Int] -> [(Int, a)]
getIndexes' [] _ = []
getIndexes' (x:xs) (y:ys) = (y, x) : (getIndexes' xs ys)

*Main> :load ListUtil.hs
[1 of 1] Compiling Main             ( ListUtil.hs, interpreted )
Ok, modules loaded: Main.
*Main> 
*Main> getIndexes ["Hari Krishna", "PTR", "Nayan", "Sudhir"]
[(1,"Hari Krishna"),(2,"PTR"),(3,"Nayan"),(4,"Sudhir")]
*Main> 

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