emps.json
emps.json
[{
"id": 1,
"firstName": "Ram",
"lastName": "Gurram",
"age": 23
},
{
"id": 2,
"firstName": "Sailaja",
"lastName": "PTR",
"age": 31
},
{
"id": 3,
"firstName": "Venkat",
"lastName": "IT",
"age": 30
},
{
"id": 4,
"firstName": "Gopi",
"lastName": "Battu",
"age": 34
}
]
a. Get all the employees whose firstName contains string ‘a’
$cat emps.json | jq '.[] | select((.firstName | contains("a")))'
{
"id": 1,
"firstName": "Ram",
"lastName": "Gurram",
"age": 23
}
{
"id": 2,
"firstName": "Sailaja",
"lastName": "PTR",
"age": 31
}
{
"id": 3,
"firstName": "Venkat",
"lastName": "IT",
"age": 30
}
b. Get all the employees whose firstName contains string ‘ai’
$cat emps.json | jq '.[] | select((.firstName | contains("ai")))'
{
"id": 2,
"firstName": "Sailaja",
"lastName": "PTR",
"age": 31
}
c. Get all the ids of employees whose name contains string ‘ai’
$cat emps.json | jq '.[] | select((.firstName | contains("ai"))) | .id'
2
d. Get all the employees firstName and lastName whose id is even number
$cat emps.json | jq '.[] | select((.id % 2 == 0)) | .firstName+","+.lastName+"," +(.id|tostring)'
"Sailaja,PTR,2"
"Gopi,Battu,4"
e. Get all the employees firstName and lastName whose id is odd number
$cat emps.json | jq '.[] | select((.id % 2 != 0)) | .firstName+","+.lastName+"," +(.id|tostring)'
"Ram,Gurram,1"
"Venkat,IT,3"
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