Approach
1: Using
concatenation
public
static String repeat(String str, int n) {
if(str == null || n <= 1) {
return str;
}
StringBuilder builder = new
StringBuilder();
for(int i = 0; i < n; i++) {
builder.append(str);
}
return builder.toString();
}
App.java
package com.sample.app; public class App { public static String repeat(String str, int n) { if(str == null || n <= 1) { return str; } StringBuilder builder = new StringBuilder(); for(int i = 0; i < n; i++) { builder.append(str); } return builder.toString(); } public static void main(String args[]) { String str = "Hello"; String repeatd3Tiimes = repeat(str, 3); System.out.println("str : " + str); System.out.println("repeatd3Tiimes : " + repeatd3Tiimes); } }
Approach
2: Using repeat
method. (This is supported from java11 onwards).
Example
String str
= "Hello";
String
repeated = str.repeat(3);
App.java
package com.sample.app; public class App { public static String repeat(String str, int n) { if (str == null || n <= 1) { return str; } StringBuilder builder = new StringBuilder(); for (int i = 0; i < n; i++) { builder.append(str); } return builder.toString(); } public static void main(String args[]) { String str = "Hello"; String repeated = str.repeat(3); System.out.println(repeated); } }
Approach
3: Using String.join and Collections.nCopies method
String.join("",
Collections.nCopies(n, str));
App.java
package com.sample.app; import java.util.Collections; public class App { public static String repeat(String str, int n) { if (str == null || n <= 1) { return str; } return String.join("", Collections.nCopies(n, str)); } public static void main(String args[]) { String str = "Hello"; String repeated = repeat(str, 3); System.out.println(repeated); } }
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