Groovy : List: max: Find maximum element in the list

Groovy provides max() method that returns the maximum element in the list. ‘max’ method available in below overloaded forms.

public Object max()

public Object max(Closure closure)

public Object max(Comparator comparator)

public Object max()

Return the maximum value in the list.

HelloWorld.groovy

numbers = [1, 100, 98, 32, 456, 78, 90]
cities = ["Bangalore", "New Delhi", "Calcutta", "Chennai", "Amaravathi"]

println "numbers.max() : ${numbers.max()}"
println "cities.max() : ${cities.max()}"

Output

numbers.max() : 456

cities.max() : New Delhi

public Object max(Closure closure)

Return the maximum value based on closure (Closure is used to determine ordering). Closure can be 1 or 2-order closure.

HelloWorld.groovy

cities = ["Bangalore", "New Delhi", "Calcutta", "Chennai", "Amaravathi"]

longestCityName = cities.max{it.length()}
cityNameByName = cities.max{a, b -> a.compareTo(b)}

println "longestCityName : $longestCityName"
println "cityNameByName : $cityNameByName"

Output

longestCityName : Amaravathi

cityNameByName : New Delhi

public Object max(Comparator comparator)

Selects the maximum value found in the Iterable using the given comparator.

HelloWorld.groovy

cities = ["Bangalore", "New Delhi", "Calcutta", "Chennai", "Amaravathi"]

Comparator nameComparator = { a, b -> a.compareTo(b) } 
Comparator lengthComparator = {a, b -> a.length()-b.length()}

cityNameByName = cities.max(nameComparator)
cityNameByLength = cities.max(lengthComparator)

println "cityNameByName : $cityNameByName"
println "cityNameByLength : $cityNameByLength"

Output

cityNameByName : New Delhi

cityNameByLength : Amaravathi

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