Groovy: Fields

Field is a member of class that satisfies below conditions.

a.   Mandatory name

b.   Mandatory access modifier like public, protected, or private

c.    One or more optional modifiers like static, final, synchronized

d.   An optional type

HelloWorld.groovy

class Employee {
 public static int noOfEmployees = 0

 private String name
 private int id
 
 public Employee() {
  noOfEmployees++
 }

 public String getName() {
  return name
 }

 public void setName(String name) {
  this.name = name
 }

 public int getId() {
  return id
 }

 public void setId(int id) {
  this.id = id
 }

}

Employee emp1 = new Employee()
emp1.setName("Krishna")
emp1.setId(123)

println "id : ${emp1.getId()}, name : ${emp1.getName()}"

Output

id : 123, name : Krishna

Can I omit the type to a field?

Yes, you can omit the type of a field, but it is recommended to specify the type.

HelloWorld.groovy

class Employee {
 public static noOfEmployees = 0

 private name
 private id
 
 public Employee() {
  noOfEmployees++
 }

 public getName() {
  return name
 }

 public setName(name) {
  this.name = name
 }

 public getId() {
  return id
 }

 public setId(id) {
  this.id = id
 }

}

Employee emp1 = new Employee()
emp1.setName("Krishna")
emp1.setId(123)

println "id : ${emp1.getId()}, name : ${emp1.getName()}"

Output

id : 123, name : Krishna

As you see above example, I omitted the type for fields and methods (omitted return type and type to the arguments) also.

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