Groovy: Check for existence of an element in the list

There are three ways to check whether an element exit in the list or not.

a.   Using in operator

b.   Using contains method

c.    Using containsAll method

Using in operator

HelloWorld.groovy

primes = [2, 3, 5, 7, 11, 13]

is2Exist = 2 in primes
is17Exist = 17 in primes
is7Exist = 7 in primes

println "is2Exist : $is2Exist"
println "is17Exist : $is17Exist"
println "is7Exist : $is7Exist"

Output

is2Exist : true

is17Exist : false

is7Exist : true

Using contains method

public boolean contains(Object item)

Returns true if this iterable contains the item.

HelloWorld.groovy

primes = [2, 3, 5, 7, 11, 13]

is2Exist = primes.contains(2)
is17Exist = primes.contains(17)
is7Exist =  primes.contains(7)

println "is2Exist : $is2Exist"
println "is17Exist : $is17Exist"
println "is7Exist : $is7Exist"

Output

is2Exist : true

is17Exist : false

is7Exist : true

Using containsAll method

HelloWorld.groovy

primes = [2, 3, 5, 7, 11, 13]

isExist = primes.containsAll([2, 7, 13])
println "Is [2, 7, 13] exist in $primes : $isExist"

isExist = primes.containsAll([2, 7, 13, 19])
println "Is [2, 7, 13, 19] exist in $primes : $isExist"

Output

Is [2, 7, 13] exist in [2, 3, 5, 7, 11, 13] : true

Is [2, 7, 13, 19] exist in [2, 3, 5, 7, 11, 13] : false

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