By
using ZipFile class, we can get all the files in a zip file.
Following
snippet is used to get all the file names is a zip file.
ZipFile
zipFile = new ZipFile(path)
for
(ZipEntry entry : Collections.list(zipFile.entries())) {
System.out.println(entry.getName());
}
Find
the following complete working application.
package com.sample; import java.io.IOException; import java.util.ArrayList; import java.util.Collections; import java.util.List; import java.util.zip.ZipEntry; import java.util.zip.ZipFile; public class ZipFileUtil { /** * * @param path * specifies the absolute path of zip file * @return empty list if path is empty/null, or if any exception comes, else * return list of file names in given zip file. */ public static List<String> getZipFiles(String path) { if (path == null || path.isEmpty()) { return Collections.emptyList(); } try (ZipFile zipFile = new ZipFile(path)) { List<String> fileNames = new ArrayList<>(); for (ZipEntry entry : Collections.list(zipFile.entries())) { fileNames.add(entry.getName()); } return fileNames; } catch (IOException e) { e.printStackTrace(); return Collections.emptyList(); } } }
package com.sample; import java.io.IOException; import java.util.List; public class Test { public static void main(String args[]) throws IOException { List<String> fileNames = ZipFileUtil.getZipFiles("C:\\Users\\Krishna\\Documents\\Project related\\sample.zip"); for(String fileName : fileNames){ System.out.println(fileName); } } }
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