It
is a 2 step process.
Step 1: Get the object from
database.
Employee
emp = (Employee)session.get(Employee.class, 1);
Step 2: Do the change you
want. Hibernate automatically updates, when you call setters.
emp.setFirstName("Shanmugham");
emp.setLastName("Chinnappaiyan");
package myFirstHibernate; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; @Entity public class Employee { @Id @GeneratedValue private int id; private String firstName; private String lastName; public int getId() { return id; } public void setId(int id) { this.id = id; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } }
hibernate.cfg.xml
<?xml version='1.0' encoding='utf-8'?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd"> <hibernate-configuration> <session-factory> <!-- Database Connection settings --> <property name="connection.driver_class">com.mysql.jdbc.Driver</property> <property name="connection.url">jdbc:mysql://localhost/sample</property> <property name="connection.username">root</property> <property name="connection.password">tiger</property> <!-- Enable the logging of all the generated SQL statements to the console --> <property name="show_sql">true</property> <!-- Format the generated SQL statement to make it more readable, --> <property name="format_sql">false</property> <!-- Hibernate will put comments inside all generated SQL statements to hint what’s the generated SQL trying to do --> <property name="use_sql_comments">false</property> <!-- This property makes Hibernate generate the appropriate SQL for the chosen database. --> <property name="dialect">org.hibernate.dialect.MySQLDialect</property> <!-- Drop and re-create the database schema on startup --> <property name="hbm2ddl.auto">create</property> <!-- mappings for annotated classes --> <mapping class="myFirstHibernate.Employee" /> </session-factory> </hibernate-configuration>
package myFirstHibernate; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.boot.registry.StandardServiceRegistryBuilder; import org.hibernate.cfg.Configuration; public class TestEmployee { /* Step 1: Create session factory */ private static SessionFactory getSessionFactory() { Configuration configuration = new Configuration().configure(); StandardServiceRegistryBuilder builder = new StandardServiceRegistryBuilder(). applySettings(configuration.getProperties()); SessionFactory factory = configuration.buildSessionFactory(builder.build()); return factory; } public static void main(String args[]){ Employee emp1 = new Employee(); Employee emp2 = new Employee(); Employee emp3 = new Employee(); emp1.setFirstName("Hari Krishna"); emp1.setLastName("Gurram"); emp2.setFirstName("Shreyas"); emp2.setLastName("Desai"); emp3.setFirstName("Piyush"); emp3.setLastName("Rai"); SessionFactory sessionFactory = getSessionFactory(); Session session = sessionFactory.openSession(); session.beginTransaction(); /* Saving objects to database */ session.save(emp1); session.save(emp2); session.save(emp3); /* Update employee with id 1 */ Employee emp = (Employee)session.get(Employee.class, 1); System.out.println(emp.getId() +" " + emp.getFirstName() + " " + emp.getLastName() +" updating...."); emp.setFirstName("Shanmugham"); emp.setLastName("Chinnappaiyan"); session.getTransaction().commit(); session.close(); } }
Run
TestEmployee class, you will get output like below.
Hibernate: drop table if exists Employee Hibernate: create table Employee (id integer not null auto_increment, firstName varchar(255), lastName varchar(255), primary key (id)) Dec 22, 2014 4:07:39 PM org.hibernate.tool.hbm2ddl.SchemaExport execute INFO: HHH000230: Schema export complete Hibernate: insert into Employee (firstName, lastName) values (?, ?) Hibernate: insert into Employee (firstName, lastName) values (?, ?) Hibernate: insert into Employee (firstName, lastName) values (?, ?) 1 Hari Krishna Gurram updating.... Hibernate: update Employee set firstName=?, lastName=? where id=?
MySQL
table structure like below.
mysql> select * from employee; +----+------------+---------------+ | id | firstName | lastName | +----+------------+---------------+ | 1 | Shanmugham | Chinnappaiyan | | 2 | Shreyas | Desai | | 3 | Piyush | Rai | +----+------------+---------------+ 3 rows in set (0.00 sec)
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