Sunday 11 May 2014

LinkedList : listIterator(int index) : Get the List Iterator from specific index

public ListIterator<E> listIterator(int index)
Returns a list-iterator of the elements in this list (in proper sequence), starting at the specified position in the list.

import java.util.*;
 
class LinkedListIterator{
 public static void main(String args[]){
  LinkedList<Integer> myList;
  myList = new LinkedList<> ();
  
  /* Add Elements to myList */
  myList.add(10);
  myList.add(20);
  myList.add(30);
  myList.add(40);
  myList.add(50);
  
  ListIterator iter = myList.listIterator(2);
  
  System.out.println("List iterator from index 2");
  System.out.println("Elements in forward direction");
  while(iter.hasNext()){
   System.out.println(iter.next());
  }
  
  System.out.println("Elements in backward direction");
  while(iter.hasPrevious()){
   System.out.println(iter.previous());
  }
 }
}

Output
List iterator from index 2
Elements in forward direction
30
40
50
Elements in backward direction
50
40
30
20
10

1. Throws IndexOutOfBoundsException if index out of range
import java.util.*;
 
class LinkedListIteratorIndexOut{
 public static void main(String args[]){
  LinkedList<Integer> myList;
  myList = new LinkedList<> ();
  
  /* Add Elements to myList */
  myList.add(10);
  myList.add(20);
  myList.add(30);
  myList.add(40);
  myList.add(50);
  
  System.out.println("List iterator from index 6");
  ListIterator iter = myList.listIterator(6);
 }
}

Output
List iterator from index 6
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 6, Size:5
        at java.util.LinkedList.checkPositionIndex(LinkedList.java:558)
        at java.util.LinkedList.listIterator(LinkedList.java:865)
        at LinkedListIteratorIndexOut.main(LinkedListIteratorIndexOut.java:16)


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