Exception
is an event that disrupts the normal flow of execution.
When
an error occurred in a method, then the method creates an exception
object, and handle it to the Java Run time system. The exception
object contains information about exception type, the line where the
exception occurred, stack trace etc.,
Example
class ExceptionEx{ void print(){ System.out.println(10/0); } void callPrint(){ print(); } public static void main(String args[]){ ExceptionEx obj = new ExceptionEx(); obj.callPrint(); } }
When
you tries to run the above program, Java Run time system throws the
below error
Exception
in thread "main" java.lang.ArithmeticException: / by zero
at
ExceptionEx.print(ExceptionEx.java:4)
at
ExceptionEx.callPrint(ExceptionEx.java:8)
at
ExceptionEx.main(ExceptionEx.java:13)
As
you observe the above error message, below things are clear.
1.
Exception Type is : ArithmeticException: / by zero
2.
The method where exception occurred is
ExceptionEx.print(ExceptionEx.java:4)
Above
line tells that exception occured in the method print.
3.
The line where exception occurred is : ExceptionEx.java:4
Where
ExceptionEx.java is the file name where error occurred and line
number 4, causes the error.
4.
Stack trace give the detailed view to find the root cause of the
exception.
Exception
in thread "main" java.lang.ArithmeticException: / by zero
at
ExceptionEx.print(ExceptionEx.java:4)
at
ExceptionEx.callPrint(ExceptionEx.java:8)
at
ExceptionEx.main(ExceptionEx.java:13)
From
the stack trace, we can sure that exception occurred in the method
print(), which is called by callPrint(), which in turn called by the
main method.
If
the program don't have any exception handling mechanism, then the
Java run time system throws the exception and terminates. That is
what happened in the above program.
No comments:
Post a Comment